Requirements: Python 3.9+
Running: python3 -m vpm < input.txt
A simple game logic example which demonstrates basic OOP techniques in Python. |
import io | |
import os.path | |
from PIL import Image | |
TEMPLATE = """ | |
<!DOCTYPE html> | |
<html> | |
<head> |
Requirements: Python 3.9+
Running: python3 -m vpm < input.txt
KBD_LAYOUT = { | |
'en': 'abcdefghijklmnopqrstuvwxyz[];\',.ABCDEFGHIJKLMNOPQRSTUVWXYZ{}:"<>`~@#$^&', | |
'ru': 'фисвуапршолдьтщзйкыегмцчняхъжэбюФИСВУАПРШОЛДЬТЩЗЙКЫЕГМЦЧНЯХЪЖЭБЮёЁ"№;:?', | |
'uk': 'фисвуапршолдьтщзйкіегмцчняхїжєбюФИСВУАПРШОЛДЬТЩЗЙКІЕГМЦЧНЯХЇЖЄБЮ\'₴"№;:?' | |
} |
# Cellular automata | |
# https://natureofcode.com/book/chapter-7-cellular-automata/ | |
def ca(rule, ncells): | |
def _next_cell(a, b, c): | |
a <<= 1 | |
a |= b | |
a <<= 1 | |
a |= c | |
return (rule & (1 << a)) >> a |
def reverse_bits(n): | |
assert 1 <= n <= 1000000000,\ | |
'argument must be in range [1, 1000000000]' | |
r = 0 | |
while n: | |
r <<= 1 | |
r |= n & 1 | |
n >>= 1 | |
return r |
def spiral(m, n): | |
""" Spiral matrix traversal (counterclockwise). """ | |
m -= 1 | |
dx, dy = 0, 1 | |
x, y = 0, -1 | |
while m >= 0 and n >= 0: | |
for _ in range(m if dx else n): | |
x += dx | |
y += dy |
from collections import namedtuple | |
from operator import itemgetter, sub | |
class rgb: | |
# https://www.w3.org/TR/REC-html40/types.html#h-6.5 | |
_NAMED_COLORS = { | |
'black': 0x000000, | |
'green': 0x008000, | |
'silver': 0xC0C0C0, |
import json | |
import math | |
import re | |
import urllib.parse | |
from collections import Counter | |
from difflib import SequenceMatcher | |
from pprint import pprint | |
from tldextract import extract as tldextract | |
from unidecode import unidecode |
import this | |
from random import choice | |
from django.conf import settings | |
from django.conf.urls import url | |
from django.core.management import execute_from_command_line | |
from django.http import HttpResponse | |
text = ''.join(this.d.get(c, c) for c in this.s) |