Created
November 28, 2015 10:43
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brutal force yöntemiyle en küçük ortak bölenin bulunması.
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| def ekok(a,b): | |
| okek=1 | |
| bolen=2 | |
| while bolen<=a and bolen <=b: | |
| if(a%bolen==0 and b%bolen==0): | |
| a=a/bolen | |
| b=b/bolen | |
| okek=okek*bolen | |
| else: | |
| if(a%bolen==0): | |
| a=a/bolen | |
| okek=okek*bolen | |
| if(b%bolen==0): | |
| b=b/bolen | |
| okek=okek*bolen | |
| bolen=bolen+1 | |
| okek=okek*a*b | |
| return int(okek) |
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