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@pablovv72
Last active November 24, 2018 12:14
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'''Hallar un número acabado en 2 que cumpla la condición de que si se desplaza
el 2 a la posición inicial el número resultante es el doble del inicial.'''
n = 42
exp = 2
while 2 * 10 ** (exp - 2) + n // 10 != n * 2:
n = (n * 20 + 2) - (n * 20 + 2) // 10 ** exp * 10 ** exp
exp += 1
print(n)
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