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padolsey/1.js

Created February 21, 2013 21:26
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A little JS [ES3] task: In each case, implement `x` so that the expression is true. Do not modify the expressions though. Post your solutions as a fork of this gist. ***Remember: ES3 only.
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2.js
x() === x()() === x()()()
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3.js
x > 2 && x < 2
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4.js
delete x.a && x.a;
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6.js
typeof new x < typeof x
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7.js
x - 1 === x + 1
@nathancerny
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typeof typeof x === 'string'

@getify
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getify commented Feb 22, 2013

ES3 only. Don't cheat. :)

@azproduction
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Late, but done :)

@lushchick
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It took some time =) Nice stuff! https://gist.github.com/lushchick/5016434

@screamy
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screamy commented Feb 23, 2013

Nice quiz
expression with delete still didn't solved

@vjeux
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vjeux commented Feb 24, 2013

Couldn't find #4 and #6: https://gist.github.com/vjeux/5022831

@frontdevops
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var x = Infinity;
x - 1 === x + 1;

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