Created
December 17, 2019 02:16
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/** | |
* Traductor de texto a binario en ANSI C | |
* | |
* @author parzibyte | |
* @see https://parzibyte.me/blog | |
* */ | |
#include <stdio.h> | |
#include <string.h> | |
/** | |
* C++ version 0.4 char* style "itoa": | |
* Written by Lukás Chmela | |
* Released under GPLv3. | |
*/ | |
char *itoa(int value, char *result, int base) { | |
// check that the base if valid | |
if (base < 2 || base > 36) { | |
*result = '\0'; | |
return result; | |
} | |
char *ptr = result, *ptr1 = result, tmp_char; | |
int tmp_value; | |
do { | |
tmp_value = value; | |
value /= base; | |
*ptr++ = "zyxwvutsrqponmlkjihgfedcba9876543210123456789abcdefghijklmnopqrstuvwxyz"[35 + | |
(tmp_value - value * base)]; | |
} while (value); | |
// Apply negative sign | |
if (tmp_value < 0) *ptr++ = '-'; | |
*ptr-- = '\0'; | |
while (ptr1 < ptr) { | |
tmp_char = *ptr; | |
*ptr-- = *ptr1; | |
*ptr1++ = tmp_char; | |
} | |
return result; | |
} | |
int main(void) { | |
// El texto que vamos a traducir | |
char *texto = "Mi nombre es Luis Cabrera Benito"; | |
printf("En texto es: %s\n", texto); | |
char *relleno = "00000000"; | |
// El número que irá tomando cada letra | |
int decimal = 0; | |
char cadena[9]; | |
int i = 0; | |
printf("En binario es: \n"); | |
while (texto[i] != '\0') { | |
decimal = (long) texto[i];// Obtener valor ASCII del carácter | |
// Convertir y almacenar el binario en "cadena" | |
itoa(decimal, cadena, 2); | |
// Diferencia para saber si no mide 8 | |
int diferencia = 8 - (int) strlen(cadena); | |
// Imprimir. El %*.*s es para rellenar la cadena con ceros a la izquierda | |
// https://stackoverflow.com/questions/276827/string-padding-in-c/9741091#9741091 | |
printf("%*.*s%s ", diferencia, diferencia, relleno, cadena); | |
i++; | |
} | |
} |
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