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@parzibyte
Last active April 15, 2020 07:47
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/*
Calcular pi usando la fórmula de Leibniz
Recuerda: entre más iteraciones, mayor precisión
*/
double calcularPi(double iteraciones) {
double numerador = 4;
double denominador = 1; // A este lo vamos a ir aumentando de 2 en 2
double pi = 0;
int x = 0;
// Recuerda que es alternar entre negativo y positivo; por eso la bandera.
// Comenzamos en positivo
int operador = 1;
for (x; x < iteraciones; x++) {
pi += operador * (numerador / denominador);
denominador += 2; // El denominador aumenta de 2 en 2
operador *= -1; // Alternamos operador
}
return pi;
}
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