Chinese Chess problem solution 1

gistfile1.c

#include <stdio.h>

void main()
{
    short unsigned int x;

    for (x = 0; (x & 0xF0) < 0x90; x += 0x10 ) {
        for ( x &= 0xF0; (x & 0x0F) < 9; x++)
            if ((x >> 4) % 3 != (x & 0x0F) % 3)
                printf("A = %d, B = %d\n", (x >> 4) + 1, (x & 0x0F) + 1);
    }
}