Javascript Remove Matching Objects from list with .filter()

javascript.filters.js

/**
Problem Statement

Javascript does not have a built in function that removes objects {} from an array with negitive conditions i.e. !=
*/

/* Example of problem */

const myArray = [ { a: 'b', 'b': 'c' }, { a: 'b', 'b': 'd' }];
const filter = { a: 'b', b: 'c'}
myArray.filter(({ a, b }) => a != filter.a && b != filter.b);

/** 
at first glance this looks like it would work, however because both objects 
within the array meet the first condition a != filter.a the second condition b != filter.b is never
checked. This results in a return of [] where we expect a return of [{ a: 'b', 'b': 'd' }]
*/

/**
Two ways of solving this are by creating any array which holds your conditions
[conditionA, conditionB] and checking if all of the values are True or False depending on which function you use
*/

/** Solution 1  Array.every 
The benefit with this case is you get to use positive checks ===
*/
const myArray = [ { a: 'b', 'b': 'c' }, { a: 'b', 'b': 'd' }, { a: 'b', 'b': 'e' }, { a: 'a', 'b': 'e' }];
const filter = { a: 'b', b: 'c'}
myArray.filter(({ a, b }) => !([a === filter.a, b === filter.b].every(Boolean)))

const result = [
    {
        "a": "b",
        "b": "d"
    },
    {
        "a": "b",
        "b": "e"
    },
    {
        "a": "a",
        "b": "e"
    }
];

/** Solution 2 Array.some 
The benefit with this solution is some should stop after finding one case which meets the condition limiting
the number of loops if you have many conditions
*/
const myArray = [ { a: 'b', 'b': 'c' }, { a: 'b', 'b': 'd' }, { a: 'b', 'b': 'e' }, { a: 'a', 'b': 'e' }];
const filter = { a: 'b', b: 'c'}
myArray.filter(({ a, b }) => ([a !== filter.a, b !== filter.b].some(Boolean)))

const result = [
    {
        "a": "b",
        "b": "d"
    },
    {
        "a": "b",
        "b": "e"
    },
    {
        "a": "a",
        "b": "e"
    }
];