Illustration of caveats of defining logger in superclass

LoggerDemo.scala

import com.typesafe.scalalogging.slf4j.Logging
import org.slf4j.LoggerFactory

class SuperClassA extends Logging {
  def doSuper {
    logger.info("Hi, SuperClassA")
  }
}

class SubClassA extends SuperClassA {
  def doSub {
    logger.info("Hi, SubClassA")
  }
}

class SuperClassB {
  def doSuper {
    logger.info("Hi, SuperClassB")
  }

  private val logger = LoggerFactory.getLogger(classOf[SuperClassB])
}

class SubClassB extends SuperClassB {
 def doSub {
    logger.info("Hi, SubClassB")
  }

  private val logger = LoggerFactory.getLogger(classOf[SubClassB])
}

object LoggerDemo {
  def main(args: Array[String]) {
    val a = new SubClassA
    a.doSuper
    a.doSub
    
    val b = new SubClassB
    b.doSuper
    b.doSub
  }
}