Cee Lo dice game

cee_lo.py

'''
Cee-lo is a gambling game played with three six-sided dice.
'''
from __future__ import print_function
import random
from collections import Counter


def input_float(msg):
    '''
    This function will loop until user enters a valid number.
    '''
    while True:
        try:
            # Nonsense to make the code python3 compatible
            try:
                number = float(raw_input(msg))
            except NameError:
                number = float(input(msg))
        except ValueError:
            pass
        else:
            break
    return number


def get_roll():
    '''
    This function will roll three dice and return the roll's value and a
    message.
    '''
    roll = 0
    msg = ''
    # Roll until a valid roll
    while roll == 0:
        #Your 3 Dice Roll
        dice = [
            random.randint(1, 6),
            random.randint(1, 6),
            random.randint(1, 6),
        ]

        msg += "This is the roll: {0} {1} {2}. ".format(*dice)

        counter = Counter(dice).most_common()

        # Rolling a 4 5 6 is an automatic win, the computer does not even
        # roll if you roll this
        if sorted(dice) == [4, 5, 6]:
            roll = 100
            msg += "{name} rolled a 4 5 6"
        # Opposite of rolling a 4 5 6, rolling a 1 2 3 is an automatic loss,
        # the computer does not roll
        elif sorted(dice) == [1, 2, 3]:
            roll = -100
            msg += "{name} rolled a 1 2 3"
        # Rolling three of a kind beats rolling any one integer, but three
        # 6s beats three 5s
        elif counter[0][1] == 3:
            roll = (counter[0][0] * 11)
            msg += "{{name}} rolled Trip {0}'s!!!".format(counter[0][0])
        # The following 3 elif statements calculate the same thing. When two
        # integers match, the unmatched integer is the score
        elif counter[0][1] == 2:
            roll = counter[1][0]
            msg += "{{name}} rolled a {0}".format(roll)
        # If none of the integers match, there is no score, reroll
        else:
            msg += "Roll Again\n"
    return roll, msg


def main():
    '''
    The main function
    '''
    fbank = input_float("Enter your Deposit: $")
    while fbank > 0:
        print("Your bank is now: ${0}".format(fbank))

        # Amount player is wagering
        fbet = input_float("How much would you like to bet?: $")

        player_roll, msg = get_roll()
        print(msg.format(name='You'))

        # The following occurs when the player rolled a 1 2 3 and
        # automatically loses
        if player_roll == -100:
            computer_roll = 0
        # The following occurs when the player rolled a 4 5 6 and
        # automatically wins
        elif player_roll == 100:
            computer_roll = 0
        # The following occurs when player rolls something else
        elif player_roll >= 1 and player_roll <= 66:
            computer_roll, msg = get_roll()
            print(msg.format(name='Computer'))

        if player_roll > computer_roll:
            fbank += fbet
            print("You win!")
        elif player_roll < computer_roll:
            fbank -= fbet
            print("You lose!")
        else:
            print("You push, Re-roll")

    print("You have no money in your bank, make a deposit to play")

if __name__ == '__main__':
    try:
        main()
    except KeyboardInterrupt:
        pass
    finally:
        print("\nThanks for playing")