Return Two Values to Function in ES6

funFunction.js

const isSpaceship = (ele) => {	
	if (ele) {
		console.log('Happy path. Ele exists.');
		let selectedOption = ele.options[ele.selectedIndex].text;
		console.log(selectedOption);
	
		if ( selectedOption == 'Raptor' || selectedOption == 'Viper') return { ready: true, value: selectedOption };
	} 

	return { ready: false };		
}

const funFunction = () => {
	const documentStatusElement = document.getElementById('vehicle-selector');	
	let { ready, value } = isSpaceship(documentStatusElement);

	switch (value) {
		case 'Raptor':
			console.log(`value: ${value}. Plan to do The Special. But first do this thing.`);
			break;
		case 'Viper':
			console.log(`value: ${value}. Plan to do The Special. But first do that thing.`);
			break;
		default:
			console.log(`value: ${value}. Do this other thing.`);
	}

	ready == true 
		? console.log(`ready: ${ready}. Do The Special.`)		
		: console.log(`ready: ${ready}. Do this other thing.`);	
}	

funFunction();