Solution to Day 4: High-Entropy Passphrases - Part 2

advent_of_code_42.py

# aoc_42.py


lines = open('input_d4.txt','r').readlines()#["abcde fghij","abcde xyz ecdab","a ab abc abd abf abj","iiii oiii ooii oooi oooo","oiii ioii iioi iiio"]#
		

lines = [w.replace('\n','').split(' ') for w in lines]
print lines
count = 0
match = True

for l in lines:
	match = True
	for j in range(len(l)):
		for k in range(j+1, len(l)):
			if l[j] == l[k]:
				match = False
				break
			elif l[j] != l[k] and ''.join(sorted(l[j]))==''.join(sorted((l[k]))):
				match = False
	if match:
		count += 1

print count