Solution to Day 11: Hex Ed - part 1

advent_of_code_d11.py

#aoc_d11.py



pos = (0,0)

inp = open('input_d11.txt','r').read().split(',')#["ne","ne","s","s"]

dic = {"ne": lambda x,y: (x+1,y+1), "n": lambda x,y: (x,y+1), "nw": lambda x,y: (x-1,y+1), 
		"w": lambda x,y: (x-1,y),
		"e": lambda x,y: (x+1,y), 
		"se": lambda x,y: (x+1,y-1), "s": lambda x,y: (x,y-1), "sw": lambda x,y: (x-1,y-1),}

for i in inp:
	pos = dic[i](pos[0],pos[1])
	#print pos

distance = max(abs(pos[0] - 0),abs(pos[1] - 0))
print distance