Solution to Day 6: Memory Reallocation - part 2
| #aoc_6.py | |
| inp=[4, 10, 4, 1, 8, 4, 9, 14, 5, 1, 14, 15, 0, 15, 3, 5] | |
| seen = [] | |
| cycles = 0 | |
| print inp | |
| while True: | |
| pattern = ','.join([str(i) for i in inp]) | |
| if pattern in seen: | |
| print cycles | |
| print len(seen)-seen.index(pattern) | |
| break | |
| cycles +=1 | |
| seen.append(pattern) | |
| maximum = max(inp) | |
| max_index = inp.index(maximum) | |
| inp[max_index] = 0 | |
| for i in range(maximum): | |
| inp[(i+max_index+1)%len(inp)] += 1 | |
| print inp |
Sign up for free
to join this conversation on GitHub.
Already have an account?
Sign in to comment