mssql_list_all_sql_agent_jobs.sql

-- list all sql agent jobs on instance
SELECT
	j.job_id,
	j.name, j.description,
	j.enabled,
	s.step_id, s.step_name, s.database_name, s.subsystem, s.command,
	j.date_created, j.date_modified,
	s.on_success_action, s.on_fail_action, s.retry_attempts, s.retry_interval, 
	s.last_run_outcome, s.last_run_duration, s.last_run_date, s.last_run_time
FROM msdb.dbo.sysjobs j WITH (NOLOCK)
INNER JOIN msdb.dbo.sysjobsteps s WITH (NOLOCK)
	ON j.job_id = s.job_id

I have a blog post using this script:
July 21, 2022, List All SQL Agent Jobs on a SQL Server Instance