get all the urls from a wedding photo website because im lazy and i wanted to download them all

lolpics.js

var urls = [];
var thumbs = $('.tab-frame-content .pg img.pv-img');
var doit = function(idx){
    if(idx < thumbs.length){
        var el = $(thumbs[idx]);
        var link = el.parent('a');
        link.trigger('mousedown');
        var timeoutID = window.setTimeout(function(){
            $('.pf-plane > .pv-ready .pv-inner > img.pv-img').each(function(){
                var style = $(this).attr('style');
                if(style){
                    urls.push(style.match(/(?:"[^"]*"|^[^"]*$)/)[0].replace(/"/g, ""));
                }
            });
            doit(idx + 1)
        }, 2000);
    }else{
        if($("a#_aab-n").css("visibility") !== "hidden"){
            $("a#_aab-n").trigger('mousedown');
            var timeoutID = window.setTimeout(function(){
                thumbs = $('.tab-frame-content .pg img.pv-img');
                doit(0);
            }, 4000);
        }else{
            console.log(urls);
        }
    }
};

doit(0);

• do that ^ in console
• prepend the url base and copy the array to clipboard:

copy(JSON.stringify(urls.map(function(url){ return "http://www.hahaha-ohwow-photos-website.com/" + url; });));

• paste in a file and save as something like pics.json
• download them all with reasonable filenames in bash:

arr=( $(cat pics.json | jq -r '.[]'))
mkdir pics
cd pics
for i in "${arr[@]}"; do echo $i; curl -O -s -S $i; done
for f in *.jpg*; do mv "$f" "${f/.jpg*/.jpg}"; done

There's probably a more clever way to rename with curl but did I mention I am laaaaaaaaaazy