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References vs values in function parameters in JS
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const assert = require("assert"); | |
// When we change the contents of an object, we can see | |
// the change outside the function. | |
function f1(obj) { | |
obj.a += 1; | |
assert.deepStrictEqual(obj, { a: 2 }); | |
} | |
const obj1 = { a: 1 }; | |
f1(obj1); | |
assert.deepStrictEqual(obj1, { a: 2 }); | |
// But when we destructure an object, we can NOT see the change | |
// outside the function. | |
function f2({ a }) { | |
a += 1; | |
assert.strictEqual(a, 2); | |
} | |
const obj2 = { a: 1 }; | |
f2(obj2); | |
assert.deepStrictEqual(obj2, { a: 1 }); | |
// This is because destructuring is requivalent to | |
// declaring a new variable and assigning the value of the | |
// property to it. | |
function f3(obj) { | |
let a = obj.a; | |
a += 1; | |
assert.strictEqual(a, 2); | |
} | |
const obj3 = { a: 1 }; | |
f3(obj3); | |
assert.deepStrictEqual(obj3, { a: 1 }); |
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