Created
September 17, 2013 21:01
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POJ 3468 A Simple Problem with Integers
http://poj.org/problem?id=3468
树状数组维护区间加减,区间求和
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#include <cstdio> | |
#include <cstring> | |
#include <iostream> | |
#include <algorithm> | |
#include <vector> | |
using namespace std; | |
const int maxn = 100100; | |
char op[10]; | |
int n, m, l, r; | |
long long x; | |
long long a[maxn], b[maxn], c[maxn]; | |
struct FenwickTree { | |
long long tree[maxn]; | |
void init(long long *a) { | |
for (int i = 0; i < maxn; i++) | |
tree[i] = a[i]; | |
} | |
void add(int x, long long val) { | |
for (int i = x; i < maxn; i += i & (-i)) | |
tree[i] += val; | |
} | |
long long sum(int x) { | |
long long res = 0; | |
for (int i = x; i > 0; i -= i & (-i)) | |
res += tree[i]; | |
return res; | |
} | |
}; | |
FenwickTree Bit1, Bit2; | |
int main() { | |
cin >> n >> m; | |
for (int i = 1; i <= n; i++) { | |
cin >> a[i]; | |
a[i] += a[i-1]; | |
} | |
Bit1.init(b); | |
Bit2.init(c); | |
for (int cas = 1; cas <= m; cas++) { | |
scanf("%s", op); | |
if (op[0] == 'Q') { | |
cin >> l >> r; | |
long long res = a[r] - a[l-1]; | |
res += (r+1)*Bit1.sum(r) - l*Bit1.sum(l-1); | |
res = res - Bit2.sum(r) + Bit2.sum(l-1); | |
cout << res << endl; | |
} else { | |
cin >> l >> r >> x; | |
Bit1.add(l, x); | |
Bit1.add(r+1, -x); | |
Bit2.add(l, x*l); | |
Bit2.add(r+1, -(r+1)*x); | |
} | |
} | |
return 0; | |
} |
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