My solutions to paiza POH 7

ando10.rb

x=1;1.upto(gets.to_i){|i|x*=i};p x

ando11.py

def get_matrix(n):
    return tuple(tuple(map(int, raw_input().strip().split())) for i in range(n))

def sub(nn, y, x, m):
    return tuple(r[x:x+m] for r in nn[y:y+m])

def search(n, nn, m, mm):
    e = n - m + 1
    for y in range(e):
        for x in range(e):
            box = sub(nn, y, x, m)
            if box == mm:
                return (y, x)

n = int(raw_input())
nn = get_matrix(n)
m = int(raw_input())
mm = get_matrix(m)
print '%d %d' % search(n, nn, m, mm)

ando12.rb

x,y,z,n=gets.strip.split.map(&:to_i)
k1=[0,x];k2=[0,y]
n.times{d,a=gets.strip.split.map(&:to_i);(d==0)?(k1<<a):(k2<<a)}
k1.sort!;k1d=1.upto(k1.size-1).map{|i| k1[i]-k1[i-1]}
k2.sort!;k2d=1.upto(k2.size-1).map{|i| k2[i]-k2[i-1]}
puts k1d.min*k2d.min*z

ando13.py

# rebase_n(144, 2) = (9, 4)
# i.e. 144 = 9 * (2 ** 4)
def rebase_n(x, n):
    c = 0
    while x % n == 0:
        c += 1
        x /= n
    return (x, c)

# x = c * (5 ** b) * (2 ** a)
def rebase_5_2(x):
    m, a = rebase_n(x, 2)
    c, b = rebase_n(m, 5)
    return (c, b, a)

def calc(n, k):
    mod = 10 ** k
    acc = [1, 0, 0]
    for i in range(1, n + 1):
        c, b, a = rebase_5_2(i)
        acc[0] = (acc[0] * c) % mod
        acc[1] += b
        acc[2] += a

    for i in range(acc[2] - acc[1]):
        acc[0] = (acc[0] * 2) % mod
    return acc[0]

def iter(n):
    for i in range(1, n+1):
        res = calc(i, 9)
        print "%s: %s" % (i, res)

n = long(raw_input())
print calc(n, 9)

ando16.rb

require 'set'
n=gets.to_i;m1=gets.to_i;s1=gets.strip.split.map(&:to_i).to_set;m2=gets.to_i;s2=gets.strip.split.map(&:to_i).to_set
s3=s2-s1;puts (s3.size==0)?'None':s3.to_a.sort.join(' ')

ando17.rb

n=gets.to_i;m=gets.to_i;r=(m%n==0)?(m/n):(m/n+1);puts 1.upto(r).map{|i|(i%2==1)?'R':'W'}.map{|e|e*n}.join[0...m]

ando2.rb

gets.to_i.times{print "Ann"}

ando4.rb

puts gets.to_i+gets.to_i

ando5.rb

a=b=0;5.times{gets[0]=='n'?(b+=1):(a+=1)};puts (a>b)?'yes':'no'

ando6.rb

gets.to_i.downto(0){|i|puts "#{i}#{'!!' if i==0}"}

ando7.rb

a,b,c,d=(gets+gets).split(/\s+/).map(&:to_f);puts (a/b>c/d)?1:2

ando9.rb

puts gets.to_i.times.map{gets.strip}.join('_')

problems.md

paiza POH 7 problems

恋愛SLG: プログラミングで彼女をつくる｜paizaオンラインハッカソン7

ando2: つり目

输入1个整数n，要求在1行内把 "Ann" 输出n遍，中间无间隔

ando4: ショートヘア

输入2个整数a和b，输出(a+b)的值

ando5: ロングヘア

输入5个投票结果(yes/no)，输出其中较多的一种

ando6: ポニーテール

输入1个数字n，输出从n到0的所有整数，每行1个，最后一行0的后面要加上"!!"

ando7: ツインテール

输入2种饮料的咖啡因含量和价格，输出性价比较高的一种

ando9: セーラー服

输入n个字符串，用下划线将它们依次连接起来并输出

ando10: カーディガン

输入1个整数n，输出它的阶乘

ando11: めがね

输入一大一小2个矩阵，已知小矩阵是大矩阵的一部分，要求输出小矩阵在大矩阵中的位置，用左上角坐标表示

ando12: サンタ服

输入一块方形蛋糕的长宽高，以及横向和纵向各切几刀、每一刀的位置，要求输出切出来的最小一块的体积

ando13: 水着

输入一个整数N，要求输出N的阶乘去掉末尾的所有0之后的最后9位数字，这9位数字前面的0也要去掉

ando16: 眼帯

输入已经持有的书籍编号和二手书店在售的书籍编号，要求输出应该购买的书籍编号，其实就是求2个集合的差集。

ando17: 縞ニーソ

已经红白相间的条纹的最大长度为m，单个条纹的长度为n，且条纹从红色开始，要求输出每个单位长度区间的颜色

test_data.txt

==> ando2.1.in <==
3

==> ando2.1.out <==
AnnAnnAnn

==> ando2.2.in <==
10

==> ando2.2.out <==
AnnAnnAnnAnnAnnAnnAnnAnnAnnAnn

==> ando4.1.in <==
9
23

==> ando4.1.out <==
32

==> ando4.2.in <==
99
100

==> ando4.2.out <==
199

==> ando5.1.in <==
yes
yes
no
yes
no

==> ando5.1.out <==
yes

==> ando5.2.in <==
no
yes
no
no
yes

==> ando5.2.out <==
no

==> ando6.1.in <==
5

==> ando6.1.out <==
5
4
3
2
1
0!!

==> ando6.2.in <==
10

==> ando6.2.out <==
10
9
8
7
6
5
4
3
2
1
0!!

==> ando7.1.in <==
200 250
180 200

==> ando7.1.out <==
2

==> ando7.2.in <==
250 200
120 150

==> ando7.2.out <==
1

==> ando9.1.in <==
3
paiza
online
hackathon

==> ando9.1.out <==
paiza_online_hackathon

==> ando9.2.in <==
2
is
Android

==> ando9.2.out <==
is_Android

==> ando10.1.in <==
4

==> ando10.1.out <==
24

==> ando10.2.in <==
3

==> ando10.2.out <==
6

==> ando11.1.in <==
4
0 0 1 0
0 1 1 0
0 1 0 1
1 1 1 0
3
0 1 1
0 1 0
1 1 1

==> ando11.1.out <==
1 0

==> ando11.2.in <==
4
0 0 0 0
0 0 1 1
0 0 1 1
0 0 0 0
2
1 1
1 1

==> ando11.2.out <==
1 2

==> ando12.1.in <==
10 10 10 2
0 3
0 8

==> ando12.1.out <==
200

==> ando12.2.in <==
20 40 10 5
1 34
1 17
0 7
1 6
0 11

==> ando12.2.out <==
240

==> ando13.1.in <==
15

==> ando13.1.out <==
307674368

==> ando13.2.in <==
10

==> ando13.2.out <==
36288

==> ando16.1.in <==
5
3
1 3 4
3
2 3 5

==> ando16.1.out <==
2 5

==> ando16.2.in <==
8
5
1 3 4 5 6
3
1 5 6

==> ando16.2.out <==
None

==> ando17.1.in <==
3
10

==> ando17.1.out <==
RRRWWWRRRW

==> ando17.2.in <==
5
4

==> ando17.2.out <==
RRRR