a263: 日期差幾天 FYI: https://yunlinsong.blogspot.com/2015/10/blog-post.html

a263.cpp

#include <cstdio>
#include <iostream>

using namespace std;

int daysPerMon[13] = {0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};

bool isLeapYear(int year)
{
	return (year % 4 == 0 && year % 100 || year % 400 == 0);
}

int daysCnt(int year, int month, int day)
{
	int sumOfDays = 0;
	for(int i = 1; i < year; i++)
	{
		bool isLeap = isLeapYear(i);

		if(isLeap)
		{
			sumOfDays += 366;
		}
		else
		{
			sumOfDays += 365;
		}
	}
	
	for(int i = 1; i < month; i++)
	{
		sumOfDays += daysPerMon[i];
	}
	
	if(isLeapYear(year) && month > 2)
		sumOfDays++;

	sumOfDays += day;
	
	//cout << "Total Days:" << sumOfDays << endl;
	return sumOfDays;
}

int dateDif(int y1, int m1, int d1, int y2, int m2, int d2)
{
	return daysCnt(y1, m1, d1) - daysCnt(y2, m2, d2);
}

int main() {
	int year[2], month[2], day[2];	
	
    while(scanf("%d%d%d %d%d%d", &year[0], &month[0], &day[0], &year[1], &month[1], &day[1]) != EOF)
	{
		int result = dateDif(year[0], month[0], day[0], year[1], month[1], day[1]);
		if( result < 0)
			result = - result;
		cout << result << endl;
	}
    return 0;
}