Very simple (and even more insecure) logging service. Just send POST request to PORT (8000 by default) and the service will log its body into log file

logr.py

import http.server
import logging
import socketserver

logging.basicConfig(filename='messages.log', format='%(levelname)s:%(asctime)s:%(message)s', level=logging.DEBUG)

class SimpleLoggingHandler(http.server.BaseHTTPRequestHandler):
    def do_POST(self):
        msg = self.rfile.read(int(self.headers['Content-Length'])).decode('UTF-8')
        logging.info(msg)

        self.send_response(204)
        self.send_header("Access-Control-Allow-Origin", "*")
        self.end_headers()

PORT = 8000

logging.info("Serving at port %s", PORT)

with socketserver.TCPServer(("", PORT), SimpleLoggingHandler) as httpd:
    httpd.serve_forever()