plediii

### Keybase proof

I hereby claim:

  * I am plediii on github.
  * I am plediii (https://keybase.io/plediii) on keybase.
  * I have a public key ASCxRulhHMZYVwHNIehhN98w4jk4Vk5l-JVpp3QE0QhooAo

To claim this, I am signing this object:

plediii

const webpack = require('webpack');
const nodeExternals = require('webpack-node-externals');
module.exports = {
    entry: './sum.test.js',
    output: {
        filename: 'bundle.test.js'
    },
    optimization: {
        minimize: false,
    },

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/* A Simple test */

import sum from './sum'


test('adds 1 + 2 to equal 3', () => {
  expect(sum(1, 2)).toBe(3);
});

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/* A simple function to test */

function sum(a, b) {
  return a + b;
}


export default sum

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@tf.function
def unitary_from_real(m):
  """Create a unitary matrix with dimensions equal to real matrix `m`"""
  return tf.linalg.expm(tf.complex(tf.transpose(m) - m, tf.transpose(m) + m))

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@tf.function
def unitary_from_real(m):
  def ihermitian_element(m, idx, jdx):
    if idx == jdx:
      return tf.complex(0., m[idx][jdx])
    elif idx < jdx:
      return tf.complex(-m[jdx][idx], m[idx][jdx])
    else:
      return tf.complex(m[idx][jdx], m[jdx][idx])
  N = m.shape[0]

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@tf.function
def unitary_from_real(m):
  def ihermitian_element(m, idx, jdx):
    if idx == jdx:
      return tf.complex(0., m[idx][jdx])
    elif idx < jdx:
      return tf.complex(-m[jdx][idx], m[idx][jdx])
    else:
      return tf.complex(m[idx][jdx], m[jdx][idx])
  N = m.shape[0]

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# First we create a random complex vector
x = tf.complex(tf.random.normal((2, 1)), tf.random.normal((2, 1)))

# Then we normalize it
quantum_bit = x / tf.sqrt(tf.reduce_sum(tf.math.conj(x) * x))

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x = tf.complex(tf.random.normal((2, 1)), tf.random.normal((2, 1)))
quantum_bit = x / tf.sqrt(tf.reduce_sum(tf.math.conj(x) * x))

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(require 'my-xml)

(add-hook 'js-mode-hook 'configure-tabs)
(add-hook 'nxml-mode-hook 'configure-tabs)

(defun configure-tabs () 
  (setq indent-tabs-mode nil))

(setq indent-tabs-mode nil)