Given a list of versions then determine the latest

LatestVersion.groovy

def latestVersion(versions) {
    def sorted = versions.sort(false) { a, b ->
        
        a = a.split('\\.')
        b = b.split('\\.')
        
        // determines how many numbers need to be compared
        def commonIndices = Math.min(a.size(), b.size())
        
        // compare each number in a version
        for (int idx = 0; idx < commonIndices; ++idx) {       
            def componentA = a[idx] as int
            def componentB = b[idx] as int
            
            if (componentA != componentB) {
                return componentA <=> componentB
            }
        }
        
        // if we escaped the loop, they are identical
        a.size() <=> b.size()   
    }
    
    // the last item is the latest
    sorted[-1]
}

assert latestVersion(["1.0", "2.0", "3.0", "4.0"]) == "4.0"
assert latestVersion(["1.0", "1.0.1", "1.1.1", "0.0.0.1", "0.1.1", "1.1.0", "1.0.3.4.5.60024"]) == "1.1.1"