Created
December 31, 2015 20:42
-
-
Save potatoqualitee/9474d62e0cbb22b76a42 to your computer and use it in GitHub Desktop.
Java final
This file contains bidirectional Unicode text that may be interpreted or compiled differently than what appears below. To review, open the file in an editor that reveals hidden Unicode characters.
Learn more about bidirectional Unicode characters
/** | |
Convert to Roman Numerals | |
Author: Chrissy LeMaire | |
Cohort: M0706 | |
FINAL PROJECT | |
Last Changed: March 10, 2007. | |
*/ | |
import java.*; | |
import java.util.*; | |
import java.lang.Math.*; | |
public class convertRoman | |
{ | |
public static void main(String args[]) | |
{ | |
String romanInput; | |
Integer runningTotal = 0,index,nextNum,currNum; | |
Character tokenizedInput; | |
/* We will use a hashmap to store the Roman Numerals and their buddies. | |
http://java.sun.com/j2se/1.4.2/docs/api/java/util/HashMap.html | |
Hashmaps are like VB's Dictionary object. They map a key to a value. | |
In this case, "C" would be a key and 100 would be the value. */ | |
HashMap<Character, Integer> map = new HashMap<Character, Integer>(); | |
// ^Stronger typing prevents compile warning: convertRoman.java uses unchecked or unsafe operations. | |
// More Info @ http://groups.google.com/group/uw.cs.cs241/msg/2fa36118400f83d1 | |
map.put('I',1); | |
map.put('V',5); | |
map.put('X',10); | |
map.put('L',50); | |
map.put('C',100); | |
map.put('D',500); | |
map.put('M',1000); | |
Scanner keyboard = new Scanner(System.in); | |
System.out.println("Type in number to convert:"); | |
System.out.println(); | |
romanInput = keyboard.nextLine().toUpperCase(); // because Java is case-sensitive | |
romanInput = romanInput.trim(); // just in case | |
for (index = 0; index < romanInput.length(); index++) | |
{ | |
/* Below we will check to see if there are more than 4 characters of the same type in a row.*/ | |
if (index+3 < romanInput.length()) // In order to not throw an exeption | |
if ( | |
romanInput.charAt(index) == romanInput.charAt(index+1) && | |
romanInput.charAt(index) == romanInput.charAt(index+2) && | |
romanInput.charAt(index) == romanInput.charAt(index+3)) | |
{ | |
System.out.println("Warning: As a general guideline, you may want to consider not using the same character four times in a row."); | |
System.out.println(""); | |
} | |
/* stringTokenizer is good for full words, but not characters. We will use a charAt index instead. | |
More info here: http://www.ling.ohio-state.edu/~kcohen/javaStringHandling.html */ | |
tokenizedInput = romanInput.charAt(index); | |
/* If the input contains anything other than IVXLCDM, Reject */ | |
if (map.containsKey(tokenizedInput) == false) | |
{ | |
System.out.println("Foo, that aint no roman numeral."); | |
System.exit(0); | |
} | |
/* Alright, Let's Start */ | |
currNum = map.get(tokenizedInput); //Convert tokenziedInput (such as "I") to its numerical value ("1") | |
/* | |
We need to follow a few rules here: | |
1. Subtract only powers of ten, such as I, X, or C. Writing VL for 45 is not allowed: write XLV instead. | |
2. Subtract only a single letter from a single numeral. Write VIII for 8, not IIX; 19 is XIX, not IXX. | |
3. Don't subtract a letter from another letter more than ten times greater. This means that you can only | |
subtract I from V or X, and X from L or C, so MIM is illegal. | |
In this code, we will "look ahead" to the next roman numeral to determine if we must subtract or add. | |
We will look ahead by using index+1, but only if index+1 isn't too big of a number. | |
*/ | |
if (index+1 < romanInput.length()) // To make sure we try to look past the last numeral. | |
{ | |
nextNum = map.get(romanInput.charAt(index+1)); //Get the next numeral | |
if(currNum >= nextNum) // if its more than or equal to, add it. | |
runningTotal = runningTotal + currNum; | |
else //otherwise, subtract it. But only if it follows the rules. | |
if ( ((Math.log(index)/Math.log(10))%1 == 0 && index>1) || (nextNum/10>currNum) ) //this addresses rule #1 and #3 | |
{ | |
System.out.println("Your roman numeral is not valid."); | |
System.exit(0); | |
} | |
else | |
{ | |
runningTotal = runningTotal + (nextNum-currNum); | |
index++; // This, by nature, takes care of rule #2 -- we never parse more than 2 at a time. | |
} | |
} | |
else | |
// It's the last character. It can only be added. | |
runningTotal = runningTotal + currNum; | |
} | |
System.out.println(runningTotal); | |
} | |
} |
Sign up for free
to join this conversation on GitHub.
Already have an account?
Sign in to comment