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a simple bit table program
use an array of 8 chars as a bit map
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/* | |
* @Copyright chm <prehistoricpenguin@qq.com> | |
* | |
* a simple bit table program | |
* use an array of 8 chars as a bit map,illuminated as below: | |
* 7 6 5 4 3 2 1 0 | |
* <--------------- | |
* 0 0 0 0 0 0 0 0 | 0 | |
* 0 0 0 0 0 0 0 0 | 1 | |
* 0 0 0 0 0 0 0 0 | 2 | |
* 0 0 0 0 0 0 0 0 | 3 | |
* 0 0 0 0 0 0 0 0 | 4 | |
* 0 0 0 0 0 0 0 0 | 5 | |
* 0 0 0 0 0 0 0 0 | 6 | |
* 0 0 0 0 0 0 0 0 | 7 | |
* ^ | |
*/ | |
#include <stdio.h> | |
#include <string.h> | |
#include <stdlib.h> | |
#include <assert.h> | |
#define TABLEROWS 8 | |
#define TABLECOLUMNS 8 | |
#define getX(val) (val >> 3) | |
#define getY(val) (val & 0x7) | |
#define setBit(val,idx) (val |= (0x1 << idx)) | |
#define getBit(val,idx) ((val >> idx) & 0x1) | |
unsigned char tbl[TABLEROWS]; | |
int setValue(int); | |
void printTable(); | |
void initTable(); | |
int main() | |
{ | |
int index; | |
initTable(); | |
printf("Table initialized as below:\n"); | |
printTable(); | |
while (1) | |
{ | |
printf("please input a value(0~63,EOF to exit):\n"); | |
if (EOF == scanf("%d", &index)) | |
break; | |
assert( index >= 0 && index <= 63); | |
if (setValue(index) == 0) | |
fprintf(stderr, "error:bit %d is already setted!\n", index); | |
else | |
{ | |
printf("bit set sucessful\n"); | |
printTable(); | |
} | |
} | |
return EXIT_SUCCESS; | |
} | |
void initTable() | |
{ | |
memset(tbl, 0, sizeof(tbl)); | |
} | |
void printTable() | |
{ | |
int i, j; | |
printf("<---------------\n"); | |
for (i = 0; i < TABLEROWS; ++i) | |
{ | |
for (j = TABLECOLUMNS - 1; j >= 0; --j) | |
printf("%d ", getBit(tbl[i], j)); | |
printf("|\n"); | |
} | |
printf(" ^\n"); | |
} | |
int setValue(int idx) | |
{ | |
int x = getX(idx), | |
y = getY(idx); | |
/* | |
* bit is already setted | |
*/ | |
if (getBit(tbl[x], y)) | |
return 0; | |
else | |
{ | |
setBit(tbl[x], y); | |
return 1; | |
} | |
} |
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