0 # zero order identity element
N_1 = O -> N
I_1 = O -> I # first order identity element
N_2 = I_1 -> N_1
E_2 = I_1 -> E_1 # second order identity element
N_3 = E_2 -> N_2
A_2 . B_2 = C_2
- analogous to addition, multiplication, etc.
- works on tensors of the same order
- produces tensor of same order
A_2(B_1) = C_1
- analogous to addition, multiplication, etc.
- works on argument tensors of order minus 1
- produces tensor of order minus 1
B_1 -> C_1 = A_2
- direct inverse of application
- analogous to subtraction, division, etc.
- produces tensor of order plus 1
A_2(B_1) = C_1
A_2 = B_1 -> C_1
B_1 -> C_1 = A_2
C_1 = A_2(B_1)
N_2(I_1) = N_1
I_1 -> N_1 = N_2
I_1 -> (N_2(I_1)) = N_2
(I_1 -> N_1)(I_1) = N_1
A_2 . B_2 =
A_2(B_2(I_1))
A_2(B_1) =
A_2 . (I_1 -> B_1)
A_2(B_1) =
A_2 . (I_1 -> B_1) =
(I_1 -> B_1) . A_2 =
(I_1 -> B_1)(A_2(I_1))
C_2(A_1 . B_1) = C_2(A_1) . C_2(B_1)
C_3(I_1 -> (A_1 . B_1)) = D_2
C_3 . (E_2 -> (I_1 -> (A_1 . B_1))) =
what does it mean to apply a higher order tensor to a minus 2 lower one?