Created
April 24, 2018 11:54
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Definition compose {A: Type} (f g: A -> A) (x: A) := f (g x). | |
Lemma comp_eq: forall (A: Type) (f g: A -> A) (x: A), compose f g x = f (g x). | |
Proof. | |
intros. | |
unfold compose. | |
exact eq_refl. | |
Qed. |
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