Python
import urllib2 | |
urlString = 'http://pshmn.com/eaFnY' | |
try: | |
handle = urllib2.urlopen(urlString) | |
handle.read() | |
handle.close() | |
except IOError: | |
print "log error" |
Sign up for free
to join this conversation on GitHub.
Already have an account?
Sign in to comment
This comment has been minimized.
Probably time to make this Python3 compatible :) You'll need to change line 9 to
print("log error")
and not useurllib2
. Cheers.