//http://www.armadillo-ko.com/2018/01/kakao-coding-test-1round-1st-solution.html

kakao_1_1.java

package algorithm;

import java.util.*;

public class Kakao1 {
	public static void main(String[] args) {
		Scanner sc = new Scanner(System.in);
		int n = sc.nextInt();
		sc.nextLine(); //flush
		
		if (!(0 <= n && n <= 16)) return;

		Kakao1 k = new Kakao1();
		int[] mapA = new int[n*n];
		int[] mapB = new int[n*n];

		int i = 0;
		StringTokenizer st = new StringTokenizer(sc.nextLine());
		while (st.hasMoreTokens()) {
			mapA[i++] = Integer.parseInt(st.nextToken());
		}
		
		i = 0;
		st = new StringTokenizer(sc.nextLine());
		while (st.hasMoreTokens()) {
			mapB[i++] = Integer.parseInt(st.nextToken());
		}

		String[] map = k.combineTwoMaps(mapA, mapB, n); 
		k.printMap(map, n);
	}

	public String[] combineTwoMaps(int[] mapA, int[] mapB, int n) {
		int a = 1; //맨 앞의 비트가 0일수 있으므로 1로해서 0을 보존함.
		int b = 1; 
		int ctn = 0;
		String[] bitSum = new String[n];
		
		for (int i = n; i <= n*n; i+=n) {
			for (int j = i-n; j <= i-1; j++) {
				a = a<<1;
				b = b<<1;
				if (mapA[j] == 1) a|=1;
				if (mapB[j] == 1) b|=1;
			}
			bitSum[ctn++] = Integer.toBinaryString(a|b);
			a = 1; //맨 앞의 비트가 0일수 있으므로 1로해서 0을 보존함.
			b = 1;
		}

		return bitSum;
	}

	public void printMap(String[] map, int n) {
		for (int i = 0; i < n; i++) {
			for (int j = 1; j< map[i].length(); j++) {
				if (map[i].charAt(j) == '1') {
					System.out.print("#");
				} else {
					System.out.print("0");
				}
			}
			System.out.println("");
		}
	}
}

#----------------------------------------------------------------------------------------------#
#python 
def kakaotalk1_1(n, arr1, arr2):
    ans = []
    for i in range(n):
        ans.append(bin(arr1[i] | arr2[i]).lstrip('0b').replace("1", "#").replace("0", " "))
    print(ans)
kakaotalk1_1(6, [46, 33, 33 ,22, 31, 50], [27 ,56, 19, 14, 14, 10])
kakaotalk1_1(5, [9, 20, 28 ,18, 11], [30 ,1, 21, 17, 28])
#----------------------------------------------------------------------------------------------#
//kotlin 버전
fun kakaotalk1_1(n: Int, arr1: Array<Int>, arr2: Array<Int>): MutableList<String> {
    var ans: MutableList<String> = mutableListOf()
    for (i in 0 until n) {
        ans.add((arr1[i] or arr2[i]).toString(2).replace("1", "#").replace("0", " "))
    }
    return ans
}
fun main(args: Array<String>) {
    print(kakaotalk1_1(6, arrayOf(46, 33, 33, 22, 31, 50), arrayOf(27, 56, 19, 14, 14, 10)))
    print(kakaotalk1_1(5, arrayOf(9, 20, 28 ,18, 11), arrayOf(30 ,1, 21, 17, 28)))
}
#----------------------------------------------------------------------------------------------#

//java 
import java.util.ArrayList;

public class kakaotalk1_1 {
    public static void main(String[] args) {
        System.out.print(kakaotalk(6, new int[]{46, 33, 33, 22, 31, 50}, new int[]{27, 56, 19, 14, 14, 10}));
    }

    public static ArrayList<String> kakaotalk(int n, int[] arr1, int[] arr2) {
        ArrayList<String> ans = new ArrayList<>();
        for (int i = 0; i < n; i++) {
            ans.add(Integer.toString(arr1[i] | arr2[i], 2).replace("1", "#").replace("0", " "));
        }
        return ans;
    }
}

//function secretMap(n, arr1, arr2) {
//    const result = [];
//    for(let i = 0; i < n; i++){
//        result[i] = (arr1[i] | arr2[i]).toString(2).replace(/1/g, '#').replace(/0/g, ' ');
//    }
//    return result;
//}
//
//console.log(secretMap(6, [46, 33, 33 ,22, 31, 50], [27 ,56, 19, 14, 14, 10]))

ans.add(Integer.toString(arr1[i] | arr2[i], 2).replace("1", "#").replace("0", " ")); 같은 경우는 다른 답을 출력할 것 같습니다.
1의 경우 의도한 값은 " 1"이겠지만 실제로는 "1"만 출력될 것 같아요.
ans.add(String.format("%16s", Integer.toString(arr1[i] | arr2[i], 2)).replace("1", "#").replace("0", " ")); 로 하시면 될 것 같습니다.