1、第一個答案是b的問題是哪一道？ 　　（a）2；（b） 3；（c）4；（d）5；（e）6 2、唯一兩道具有連續相同答案的題目是？ 　　（a）2，3；（b）3，4；（c）4，5；（d）5，6；（e）6，7； 　 3、本題答案與哪一題相同？ 　　（a）1；（b）2；（c）4；（d）7；（e）6 　 4、答案是a的問題個數是？　　（a）0；（b）1；（c）2；（d）3；（e）4 　 5、本題答案與哪一題相同？　　（a）10；（b）9；（c）8；（d）7；（e）6 　 6、答案是a的問題數量與答案是什麼的問題數量相同？ 　　（a）b；（b）c；（c）d；（d）e；（e）以上都不是 　 7、按照字母順序，本題答案與下一題相差幾個字母？ 　　（a）4；（b）3；（c）2；（d）1；（e）0。（注…

gistfile1.py

import itertools

candidates = itertools.product('abcde', repeat=10)
for c in candidates:
    if q1(c) and q2(c) and q3(c) and q4(c) and q5(c) and q6(c) and q7(c) and q8(c) and q9(c) and q10(c):
        print(c)

def q1(candidate):
    this_answer = candidate[0]
    answers = { 'a':2, 'b':3, 'c':4, 'd':5, 'e':6 }
    numQuestionWithAnwserB = answers[this_answer]; 
    return candidate[numQuestionWithAnwserB-1] == 'b';

def q2(candidate):
    this_answer = candidate[1]
    numQuestionWithSameAnwser = 0;
    for i in range(len(candidate)-1):
        if candidate[i] == candidate[i+1]:
            if numQuestionWithSameAnwser != 0:
                return False
            else:
                numQuestionWithSameAnwser = i + 1 
    answers = { 'a':2, 'b':3, 'c':4, 'd':5, 'e':6 }
    return answers[this_answer] == numQuestionWithSameAnwser

def q3(candidate):
    this_answer = candidate[2]
    answers = { 'a':1, 'b':2, 'c':4, 'd':7, 'e':6 }
    return candidate[answers[this_answer]-1] == this_answer; 

def q4(candidate):
    this_answer = candidate[3]
    answers = { 'a':0, 'b':1, 'c':2, 'd':3, 'e':4 }
    return answers[this_answer] == candidate.count('a')

def q5(candidate):
    this_answer = candidate[4]
    answers = { 'a':10, 'b':9, 'c':8, 'd':7, 'e':6 }
    return candidate[answers[this_answer]-1] == this_answer; 

def q6(candidate):
    this_answer = candidate[5]
    #answers = { 'a':'b', 'b':'c', 'c':'d', 'd':'e', 'e':'' }
    #cntAns = { ans:candidate.count(ans) for ans in 'abcde' }
    #cntAnsA = cntAns['a']
    answers = { 'a':1, 'b':2, 'c':3, 'd':4 }
    cntAns = [ candidate.count(ans) for ans in 'abcde' ]
    cntAnsA = cntAns[0]
    if this_answer != 'e':
        return cntAnsA == cntAns[answers[this_answer]]
    else:
        return cntAns.count(cntAnsA) == 1

def q7(candidate):
    this_answer = candidate[6]
    answers = { 'a':4, 'b':3, 'c':2, 'd':1, 'e':0 }
    return abs(ord(this_answer) - ord(candidate[7])) == answers[this_answer]

def q8(candidate):
    this_answer = candidate[7]
    answers = { 'a':2, 'b':3, 'c':4, 'd':5, 'e':6 }
    return candidate.count('a') + candidate.count('e') == answers[this_answer]

def q9(candidate):
    this_answer = candidate[8]
    q8_answers = { 'a':2, 'b':3, 'c':4, 'd':5, 'e':6 }
    q8_value = q8_answers[candidate[7]]
    # base on q8 and assume there's only one correct answer for each questions.
    answers = { 'a':7, 'b':6, 'c':4, 'd':8, 'e':0 }
    return answers[this_answer] + q8_value == 10

def q10(candidate):
    return True