Send Email - Amazon SES SMTP Endpoint (TLS)

sendEmailAws.py

  # 
  # to send emails via Amazon SES SMTP (TLS)
  #
  
  def sendMail(self, subject, email_content):

        import smtplib
        from email.MIMEMultipart import MIMEMultipart
        from email.MIMEBase import MIMEBase
        from email import Encoders
        from email.MIMEText import MIMEText
        from email.Utils import COMMASPACE, formatdate
        
        receipients = ['onlyou@gist.com','whyme@gist.com']
        smtp_server = 'email-smtp.us-east-1.amazonaws.com'
        from_email = 'noreply@gmail.com'
        smtp_port = '587'
        smtp_username = USER_NAME
        smtp_password = PASSWORD
        
        msg = MIMEMultipart()
        msg['From'] = from_email
        msg['To'] = COMMASPACE.join(receipients)
        msg['Date'] = formatdate(localtime=True)
        msg['Subject'] = subject

        msg.attach(MIMEText(email_content))

        #for file in files:
        #    part = MIMEBase('application', "octet-stream")
        #    part.set_payload(open(file, "rb").read())
        #    Encoders.encode_base64(part)
        #    part.add_header('Content-Disposition', 'attachment; filename="%s"'
        #               % os.path.basename(file))
        #    msg.attach(part)

        smtp =smtplib.SMTP(
            host = smtp_server,
            port = smtp_port,
            timeout = 10 
            )
        
        smtp.set_debuglevel(10)
        smtp.starttls()
        smtp.ehlo()
        
        smtp.login(smtp_username, smtp_password)
        
        msg = msg.as_string()
        msg = msg.replace("text/plain", "text/html")
 
        smtp.sendmail(from_email, receipients, msg)
        smtp.close()