Normally you can't remove items from a dictionary while you are iterating over it. But if you convert it to a list first, there are no problems.

iterate and pop dict.py

origDict = { 
    'First name': 'Ryan',
    'Last name': 'M',
    'Subject': 'AI',
    'task': 'Cleaning Data'
 }
removedItem = origDict.pop('Last name') # this is normal usage of pop()
print(origDict)
print('value = ' + removedItem)

# now lets loop and pop()
newDict = {} # create a new empty dictionary for us to dump our items() into

# create a list comprehension to build a list from the original dictionary that holds the data we want to process.
tmp = [(k, v) for k, v in origDict.items()]

# now instead of looping through the dictionary,
# we loop through the list 
# and pop items out of the original dictionary as we add items to the new dictionary!
for k, v in tmp:
    # you can process the data here, before you put it in another dictionary.
    newDict[k] = origDict.pop(k, v) 
# in Python, pop() removes an item from a list/dictionary and returns it. In this case we are stuffing it into a new
# dictionary right away.


# Or you can put the comprehension in the loop!
for k, v in [(k, v) for k, v in origDict.items()]:
    newDict[k] = origDict.pop(k, v)

print(origDict)
print(newDict)

One way could be the following:

def my_filter(value):
    # Check here if the item should be removed
    pass

def process(k, value):
    # Define here how to process the item
    pass

newDict = {k: process(k, origDict.pop(k)) for k in list(origDict.keys()) if my_filter(origDict[k])}

Thanks, this is really useful!