工作需要，每个库文件都需要生成单独的cfg文件，并且需要筛选目录下存在的库文件，对比文档里的库文件对应的id，生成内容为“id,4(level)”的cfg文件。 注：这次是在sublime Text2里添加了PEP8的插件，从此开始注重编码规范

cfg_create.py

# -*-coding:utf-8 -*-
import os

path = r"C:\Users\alex\Desktop\debug"
original_file = open(r"module.txt", "r")  # read file
content = original_file.readlines()


def lib_list_without_so(yourdir):
    """ Create a list which contains all the libs without '.so'
        Call lib_list_without_so(dir)
        For an example, if there is some files like "libaaa.so",
        "libbbb.so" in that path "dir", call this function will return a link,
        which contains ["aaa","bbb"]
    """
    file_list = os.listdir(yourdir)
    new_lib_so = []
    for i in file_list:
        new_lib_so.append(i[3:-3])  # add items without .so to the new list
    return new_lib_so


def cfg_creater():
    """Create cfg files if there are ids in the txt file,
    the cfg name is the lib name.
    """
    libList = lib_list_without_so(path)  # Call the function to create lib list
    for item in content:
        if item.startswith("0"):  # Judge whether current lib has id
            item = item.strip('\n').split("\t")
            if item[1] in libList:
                # Hexadecimal numbers need to remain format:
                # 0x (lowercase) + number (uppercase)
                file_cont = (item[0][:2].lower() + item[0][2:].upper()) + ",4"
                file_name = item[1] + ".cfg"  # Define .cfg file's name
                new_file = open(file_name, "w")  # Create .cfg file
                new_file.write(file_cont)
                new_file.close()


if __name__ == '__main__':
    cfg_creater()