Password brute-force in Python

bruteforce.py

"""
Password brute-force algorithm.

List of most probable passwords and english names can be found, respectively, at:
- https://github.com/danielmiessler/SecLists/blob/master/Passwords/probable-v2-top12000.txt
- https://github.com/dominictarr/random-name/blob/master/middle-names.txt

Author: Raphael Vallat
Date: May 2018
Python 3
"""
import string
from itertools import product
from time import time
from numpy import loadtxt


def product_loop(password, generator):
    for p in generator:
        if ''.join(p) == password:
            print('\nPassword:', ''.join(p))
            return ''.join(p)
    return False


def bruteforce(password, max_nchar=8):
    """Password brute-force algorithm.

    Parameters
    ----------
    password : string
        To-be-found password.
    max_nchar : int
        Maximum number of characters of password.

    Return
    ------
    bruteforce_password : string
        Brute-forced password
    """
    print('1) Comparing with most common passwords / first names')
    common_pass = loadtxt('probable-v2-top12000.txt', dtype=str)
    common_names = loadtxt('middle-names.txt', dtype=str)
    cp = [c for c in common_pass if c == password]
    cn = [c for c in common_names if c == password]
    cnl = [c.lower() for c in common_names if c.lower() == password]

    if len(cp) == 1:
        print('\nPassword:', cp)
        return cp
    if len(cn) == 1:
        print('\nPassword:', cn)
        return cn
    if len(cnl) == 1:
        print('\nPassword:', cnl)
        return cnl

    print('2) Digits cartesian product')
    for l in range(1, 9):
        generator = product(string.digits, repeat=int(l))
        print("\t..%d digit" % l)
        p = product_loop(password, generator)
        if p is not False:
            return p

    print('3) Digits + ASCII lowercase')
    for l in range(1, max_nchar + 1):
        print("\t..%d char" % l)
        generator = product(string.digits + string.ascii_lowercase,
                            repeat=int(l))
        p = product_loop(password, generator)
        if p is not False:
            return p

    print('4) Digits + ASCII lower / upper + punctuation')
    # If it fails, we start brute-forcing the 'hard' way
    # Same as possible_char = string.printable[:-5]
    all_char = string.digits + string.ascii_letters + string.punctuation

    for l in range(1, max_nchar + 1):
        print("\t..%d char" % l)
        generator = product(all_char, repeat=int(l))
        p = product_loop(password, generator)
        if p is not False:
            return p


# EXAMPLE
start = time()
bruteforce('sunshine') # Try with '123456' or '751345' or 'test2018'
end = time()
print('Total time: %.2f seconds' % (end - start))

Tolong buat lebih sederhana... Saya baru di di bidang ini

Hi, I just tested your program, it defines a bruteforce subprogram that can be used to bruteforce a known password and see how long it takes to do it (the example at the end shows how it works with passwords you enter yourself), but how can you use this program to actually crack an unknown password?

Can i use this code in VSC?

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Where do I download it????