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Difference between dates (Not using Built-In Functions and Lists)
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#!/usr/bin/python | |
# This program is written without using any built-in functions | |
# Not using Lists, as a practice for students learning Python | |
def isLeapYear(year): | |
if ((year%4 == 0 and year%100 != 0)) or year%400 == 0: | |
return True | |
return False | |
def daysInMonth(year, month): | |
if month in {1,3,5,7,8,10,12}: | |
days = 31 | |
if month in {4,6,9,11}: | |
days = 30 | |
if month == 2: | |
if isLeapYear(year): | |
days = 29 | |
else: | |
days = 28 | |
return days | |
def nextDay(year, month, day): | |
if day < daysInMonth(year, month): | |
return year, month, day + 1 | |
else: | |
if month == 12: | |
return year + 1, 1, 1 | |
else: | |
return year, month + 1, 1 | |
def dateIsBefore(year1, month1, day1, year2, month2, day2): | |
"""Returns True if year1-month1-day1 is before | |
year2-month2-day2. Otherwise, returns False.""" | |
if year1 < year2: | |
return True | |
if year1 == year2: | |
if month1 < month2: | |
return True | |
if month1 == month2: | |
return day1 < day2 | |
return False | |
def daysBetweenDates(year1, month1, day1, year2, month2, day2): | |
"""Returns the number of days between year1/month1/day1 | |
and year2/month2/day2. Assumes inputs are valid dates | |
in Gregorian calendar.""" | |
# program defensively! Add an assertion if the input is not valid! | |
assert not dateIsBefore(year2, month2, day2, year1, month1, day1) | |
diff = 0 | |
while dateIsBefore(year1, month1, day1, year2, month2, day2): | |
year1, month1, day1 = nextDay(year1, month1, day1) | |
diff += 1 | |
return diff | |
print daysBetweenDates(2011,6,30,2012,6,30) |
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