Created
April 11, 2019 22:41
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silly identity stuff
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open function | |
variables {α β : Type} | |
def inverse (g : β → α) (f : α → β) := left_inverse g f ∧ right_inverse g f | |
def inverse_comp (f : α → β) (g : β → α) (gf_inv : inverse g f) | |
: (∀ a, (g ∘ f) a = a) ∧ (∀ b, (f ∘ g) b = b) := | |
⟨gf_inv.left, gf_inv.right⟩ | |
def inverse_comp_id {f : α → β} {g : β → α} (gf_inv : inverse g f) | |
: (g ∘ f = id) ∧ (f ∘ g = id) | |
:= ⟨funext (λ a, by rw [(inverse_comp f g gf_inv).left, id]), | |
funext (λ b, by rw [(inverse_comp f g gf_inv).right, id])⟩ | |
/- A dumb example, if inverse (f ∘ g) (f ∘ g) | |
and (f ∘ g) = id, | |
and id = (g ∘ f) | |
why not transitively, inverse (f ∘ g) (g ∘ f) | |
-/ | |
def inverse_comp_inv {α : Type*} {β : Type*} | |
: ∀ (f : α → β) (g : β → α), inverse f g → inverse (f ∘ g) (f ∘ g) | |
:= (λ f g, λ inv, | |
/- because the types differ, -/ | |
have comp_fg : β → β, from f ∘ g, | |
have comp_gf : α → α, from g ∘ f, | |
-- where as for id we have something like: | |
have id' : ∀(z : Type), z → z, from @id, | |
have fog_eq_id : (f ∘ g = id), from (inverse_comp_id inv).left, | |
have gof_eq_id : (id = g ∘ f), from eq.symm ((inverse_comp_id inv).right), | |
-- So this eq.trans isn't going to type check, even though we have proofs of the necessary arguments. | |
-- have fog_eq_gof : (f ∘ g) = g ∘ f, from eq.trans fog_eq_id gof_eq_id, | |
have fog_comp_id : ∀ x, (f ∘ g)((f ∘ g) x) = x, | |
from (λ x, calc (f ∘ g) ((f ∘ g) x) = (id (id x)) : by rw (inverse_comp_id inv).left | |
... = id x : by refl | |
... = x : by refl), | |
and.intro fog_comp_id fog_comp_id) |
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