None of the string methods modify this
– they always return fresh strings.
-
charAt(pos: number): string
ES1Returns the character at index
pos
, as a string (JavaScript does not have a datatype for characters).str[i]
is equivalent tostr.charAt(i)
and more concise (caveat: may not work on old engines).> 'abc'.charAt(1) 'b'
-
charCodeAt(pos: number): number
ES1Returns the 16-bit number (0–65535) of the UTF-16 code unit (character) at index
pos
.> 'abc'.charCodeAt(1) 98
-
codePointAt(pos: number): number | undefined
ES6Returns the number of the Unicode code point of the 1–2 characters at index
pos
. If there is no such index, it returnsundefined
. -
concat(...strings: string[]): string
ES3Returns the concatenation of
this
andstrings
.'a'+'b'
is equivalent to'a'.concat('b')
and more concise.> 'ab'.concat('cd', 'ef', 'gh') 'abcdefgh'
-
endsWith(searchString: string, endPos=this.length): boolean
ES6Returns
true
ifthis
ends withsearchString
at indexendPos
andfalse
, otherwise.> 'foo.txt'.endsWith('.txt') true > 'abc'.endsWith('ab', 2) true
-
includes(searchString: string, startPos=0): boolean
ES6Returns
true
ifthis
contains thesearchString
andfalse
, otherwise. The search starts atstartPos
.> 'abc'.includes('b') true > 'abc'.includes('b', 2) false
-
indexOf(searchString: string, minIndex=0): number
ES1Returns the lowest index at which
searchString
appears withinthis
, or-1
, otherwise. Any returned index will beminIndex
or higher.> 'abab'.indexOf('a') 0 > 'abab'.indexOf('a', 1) 2 > 'abab'.indexOf('c') -1
-
lastIndexOf(searchString: string, maxIndex=Infinity): number
ES1Returns the highest index at which
searchString
appears withinthis
, or-1
, otherwise. Any returned index will bemaxIndex
or lower.> 'abab'.lastIndexOf('ab', 2) 2 > 'abab'.lastIndexOf('ab', 1) 0 > 'abab'.lastIndexOf('ab') 2
-
match(regExp: string | RegExp): RegExpMatchArray | null
ES3If
regExp
is a regular expression with flag/g
not set then.match()
returns the first match forregExp
withinthis
. Ornull
if there is no match. IfregExp
is a string, it is converted to a regular expression before performing the previous steps.The result has the following type:
interface RegExpMatchArray extends Array<string> { index: number; input: string; groups: undefined | { [key: string]: string }; }
Numbered capture groups become Array indices. Named capture groups (ES2018) become properties of
.groups
. In this mode,.match()
works likeRegExp.prototype.exec()
.Examples:
> 'ababb'.match(/a(b+)/) [ 'ab', 'b', index: 0, input: 'ababb', groups: undefined ] > 'ababb'.match(/a(?<foo>b+)/) [ 'ab', 'b', index: 0, input: 'ababb', groups: { foo: 'b' } ] > 'abab'.match(/x/) null
-
match(regExp: RegExp): string[] | null
ES3If flag
/g
ofregExp
is set,.match()
returns either an Array with all matches ornull
if there was no match.> 'ababb'.match(/a(b+)/g) [ 'ab', 'abb' ] > 'ababb'.match(/a(?<foo>b+)/g) [ 'ab', 'abb' ] > 'abab'.match(/x/g) null
-
normalize(form: 'NFC'|'NFD'|'NFKC'|'NFKD' = 'NFC'): string
ES6Normalizes
this
according to the Unicode Normalization Forms. -
padEnd(len: number, fillString=' '): string
ES2017Appends
fillString
tothis
until it has the desired lengthlen
.> '#'.padEnd(2) '# ' > 'abc'.padEnd(2) 'abc' > '#'.padEnd(5, 'abc') '#abca'
-
padStart(len: number, fillString=' '): string
ES2017Prepends
fillString
tothis
until it has the desired lengthlen
.> '#'.padStart(2) ' #' > 'abc'.padStart(2) 'abc' > '#'.padStart(5, 'abc') 'abca#'
-
repeat(count=0): string
ES6Returns a string that is
this
, repeatedcount
times.> '*'.repeat() '' > '*'.repeat(3) '***'
-
replace(searchValue: string | RegExp, replaceValue: string): string
ES3Replace matches of
searchValue
withreplaceValue
. IfsearchValue
is a string, only the first verbatim occurrence is replaced. IfsearchValue
is a regular expression without flag/g
, only the first match is replaced. IfsearchValue
is a regular expression with/g
then all matches are replaced.> 'x.x.'.replace('.', '#') 'x#x.' > 'x.x.'.replace(/./, '#') '#.x.' > 'x.x.'.replace(/./g, '#') '####'
Special characters in
replaceValue
are:$$
: becomes$
$n
: becomes the capture of numbered groupn
(alas,$0
does not work)$&
: becomes the complete match$`
: becomes everything before the match$'
: becomes everything after the match
Examples:
> 'a 2018-04 b'.replace(/([0-9]{4})-([0-9]{2})/, '|$2|') 'a |04| b' > 'a 2018-04 b'.replace(/([0-9]{4})-([0-9]{2})/, '|$&|') 'a |2018-04| b' > 'a 2018-04 b'.replace(/([0-9]{4})-([0-9]{2})/, '|$`|') 'a |a | b'
Named capture groups (ES2018) are supported, too:
$<name>
becomes the capture of named groupname
Example:
> 'a 2018-04 b'.replace(/(?<year>[0-9]{4})-(?<month>[0-9]{2})/, '|$<month>|') 'a |04| b'
-
replace(searchValue: string | RegExp, replacer: (substr: string, ...args: any[]) => string): string
ES3If the second parameter is a function occurrences are replaced with the strings it returns. Its parameters are:
all
: the complete matchg1
,g2
, etc.: whatever was captured by numbered group 1, etc.offset
: where was the match found in the input string?string
: the whole input string
> 'a 2018-04 b'.replace(/([0-9]{4})-([0-9]{2})/, (all, year, month) => '|'+all+'|') 'a |2018-04| b'
Named capture groups (ES2018) are supported, too. If there are any, a last parameter contains an object whose properties contain the captures:
> const replacer = (...args) => { const groups=args.pop(); return '|'+groups.month+'|' }; > 'a 2018-04 b'.replace(/(?<year>[0-9]{4})-(?<month>[0-9]{2})/, replacer) 'a |04| b'
-
search(regExp: string | RegExp): number
ES3Returns the index at which
regExp
occurs withinthis
. IfregExp
is a string, it is converted to a regular expression.> 'a2b'.search(/[0-9]/) 1 > 'a2b'.search('[0-9]') 1
-
slice(start=0, end=this.length): string
ES3Returns the substring of
this
that starts at (including) indexstart
and ends at (excluding) indexend
. You can use negative indices where-1
meansthis.length-1
(etc.).> 'abc'.slice(1, 3) 'bc' > 'abc'.slice(1) 'bc' > 'abc'.slice(-2) 'bc'
-
split(separator: string | RegExp, limit?: number): string[]
ES3Splits
this
into an Array of substrings – the strings that occur between the separators. The separator can either be a string or a regular expression. Captures made by groups in the regular expression are included in the result.> 'abc'.split('') [ 'a', 'b', 'c' ] > 'a | b | c'.split('|') [ 'a ', ' b ', ' c' ] > 'a | b | c'.split(/ *\| */) [ 'a', 'b', 'c' ] > 'a | b | c'.split(/( *)\|( *)/) [ 'a', ' ', ' ', 'b', ' ', ' ', 'c' ]
-
startsWith(searchString: string, startPos=0): boolean
ES6Returns
true
ifthis
starts withsearchString
at indexstartPos
andfalse
, otherwise.> '.gitignore'.startsWith('.') true > 'abc'.startsWith('bc', 1) true
-
substring(start: number, end=this.length): string
ES1Use
.slice()
instead of this method..substring()
wasn’t implemented consistently in older engines and doesn’t support negative indices. -
toUpperCase(): string
ES1Returns a copy of
this
in which all lowercase alphabetic characters are converted to uppercase. How well that works for various alphabets depends on the JavaScript engine.> '-a2b-'.toUpperCase() '-A2B-' > 'αβγ'.toUpperCase() 'ΑΒΓ'
-
toLowerCase(): string
ES1Returns a copy of
this
in which all uppercase alphabetic characters are converted to lowercase. How well that works for various alphabets depends on the JavaScript engine.> '-A2B-'.toLowerCase() '-a2b-' > 'ΑΒΓ'.toLowerCase() 'αβγ'
-
trim(): string
ES5Returns a copy of
this
in which all leading and trailing whitespace is removed.> '\r\n# \t'.trim() '#'
- String methods of various ECMAScript versions in detail: http://exploringjs.com
- https://github.com/Microsoft/TypeScript/blob/master/lib/lib.es6.d.ts
- MDN
- ECMAScript spec
So to replace all '.'
we need to skip the special character like this.