CodinGame - Easy - Power of Thor (JavaScript)

Power of Thor.js

var inputs = readline().split(' ');
var LX = parseInt(inputs[0]);
var LY = parseInt(inputs[1]);
var TX = parseInt(inputs[2]);
var TY = parseInt(inputs[3]);

while (true) {
    var E = parseInt(readline());
    if (TY == LY) {
        if (TX < LX) {
            print('E');
            TX++; 
        } else { 
            print('W') 
            TX--;
        }
    } else if (TY > LY) {
        if (TX == LX) {
            print('N');
            printErr(TY); 
            TY--;
        } else if (TX > LX) {
            print('NW');
            TX--;
            TY--;
        } else {
            print('NE');
            TX++;
            TY--;
        }
    } else if (TY < LY) {
        if (TX == LX) {
            print('S');
            TY++;
        } else if (TX > LX) {
            print('SW');
            TX--;
            TY++;
        } else {
            print('SE');
            TX++;
            TY++;
        }
    }
}

It is so that when it is doing the IF check it is making sure that the new coordinate of Thor is still greater/less than the light. If it did not add one to the position when he moved then it would always be a passing case, and Thor would move off the field.

@RayRayG Lol dude, I don't mean to be rude, but this is a code golf challenge and you're supposed to solve it in the least amount of characters.

Example 1 (91 characters, but with cheating, cause it uses hardcoded values):
o={7:'W',5:'S'},a=+readline()[0];for(i=0;;i++)print(a>3?o[a]:a?i>13?'E':'SE':i>16?'W':'SW')

Example 2 (173 characters, but without cheating and without hardcoding anything, and could be further improved):
c=readline().split(' ').map(Number);while(1)(c[3]>c[1]?(d='N',c[3]--):(c[3]<c[1]?(d='S',c[3]++):d=''))+(c[2]>c[0]?(d+='W',c[2]--):(c[2]<c[0]?(d+='E',c[2]++):d+='')),print(d)