rayjcwu

import Ember from 'ember';

export default Ember.Controller.extend({
  appName: 'Ember Twiddle',
  
  inputValue: '',
  
  mouseUpCount: 0,
  
  mouseOverCount: 0,

rayjcwu

{
"type": "FeatureCollection",
"crs": { "type": "name", "properties": { "name": "urn:ogc:def:crs:EPSG::102008" } },
"features": [
{ "type": "Feature", "properties": { "name": "Abilene-sweetwater", "latitude": 32.404348, "tvperc": 89.2, "dma": 662, "dma1": "Abilene-Sweetwater, TX", "cableperc": 38.2, "adsperc": 51.8, "longitude": -99.8293625, "woeid": "24701160", "id": "24701160" }, "geometry": { "type": "Polygon", "coordinates": [ [ [ -241949.712413945380831, -968504.571903971140273 ], [ -273678.904670911259018, -994063.712760299793445 ], [ -294117.95397367834812, -992237.657947928877547 ], [ -301759.874027342826594, -1000327.639050370897166 ], [ -329881.11736338539049, -992670.775121580692939 ], [ -336211.2980738246697, -979745.653697608504444 ], [ -384409.521632804593537, -977149.374085129587911 ], [ -381821.615684330812655, -919272.881358372047544 ], [ -467139.32645374146523, -914452.942907638964243 ], [ -460539.450352249841671, -812716.538863145629875 ], [ -402441.160641287046019, -815688.869402655167505 

rayjcwu

{
  "type": "FeatureCollection",
  "features": [
    {
      "type": "Feature",
      "id": "Abilene-sweetwater",
      "properties": {
        "name": "Abilene-sweetwater",
        "latitude": 32.404348,
        "tvperc": 89.2,

rayjcwu

Given an input string, return the commands need to input the string in a dvr. Commands are “l”, “r”, “u”, “d”, and “*”.

input was "bad" -> "r*l*rrr*"

[a] b  c  d  e
 f  g  h  i  j
 k  l  m  n  o
 p  q  r  s  t
 u  v  w  x  y
 z

rayjcwu

public boolean lastIsSingleByteChar(byte[] bytes) {
  final int N = bytes.length;
  if (N == 0) {
    throw new IllegalArgumentException();
  }
  if (N == 1) {
    return true;
  }

  int i = N - 1;

rayjcwu

Given a 2d array as a maze with '. (open space)' and 'G (guard)', update each open spaces with the distance to its nearest guard.
Example -> 
matrix : 
.  .  .  G .
.  .  G .  .
.  .  .  . G
answer -> 
2  1  1  G  1
2  1  G  1  1
2  1  1  1  G

rayjcwu

FILE* open (char* filename);
int write(FILE* fd, char* str);
int close(FILE* fd);

class File {
  FILE* fd;
public:
  File(string filename) {
    fd = open(filename.to_c_str());
  }

rayjcwu

class Node {
  Node left;
  Node right;
  int treeSize;
  int val;
}

public float getMedian(Node root) {
  if (root == null) {
    return 0; // not sure how you want to handle empty tree

rayjcwu

public int countPair(int[] A, int X) {
  int small = 0;
  int big = 0;
  int count = 0;
  // find max big such that A[0] + A[big] <= X
  while (big + 1 < A.length && A[0] + A[big + 1] <= X) {
    big++;
  }

  // count use A[small] as smallest number, A[small + 1: big] as bigger number

rayjcwu

public class IncreasingSubarray {
  public static void main(String[] argv) {
    IncreasingSubarray is = new IncreasingSubarray();
    System.out.println(is.solution(new int[]{2, 2, 2, 2, 1, 2, -1, 2, 1, 3}));
    System.out.println(is.solution(new int[]{30, 20, 10}));
    System.out.println(is.solution(new int[]{30}));

    System.out.println(is.solution(new int[]{1, 2, 3, 4, 1, 2, 3, 4, 5}));
  }
  public int solution(int[] A) {