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[python] start debugger on exception
#
# original: http://code.activestate.com/recipes/65287/
#
# place in lib/python2.x/sitecustomize.py
import bdb
import sys
def info(type, value, tb):
if hasattr(sys, 'ps1') \
or not sys.stdin.isatty() \
or not sys.stdout.isatty() \
or not sys.stderr.isatty() \
or issubclass(type, bdb.BdbQuit) \
or issubclass(type, SyntaxError):
# we are in interactive mode or we don't have a tty-like
# device, so we call the default hook
sys.__excepthook__(type, value, tb)
else:
import traceback, pdb
# we are NOT in interactive mode, print the exception...
traceback.print_exception(type, value, tb)
print
# ...then start the debugger in post-mortem mode.
pdb.pm()
sys.excepthook = info
@ourway

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ourway commented Jan 4, 2014

great. I am looking a way to implement this as a python argument. for example:
python -pm script.py
Any idea?

@schinckel

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schinckel commented Jan 21, 2014

I test for an environment variable, which means I can just use:

AUTOPDB=true python script.py

Not quite an argument, but easy to do on a once-off basis (or, indeed, set for a shell session).

@schinckel

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schinckel commented Jan 21, 2014

Or, you could put it into a module called 'pm.py' in your path, and do it as:

python -mpm script.py

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