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algorithm_string_longest_common_prefix
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public class Solution { | |
public String longestCommonPrefix(String[] strs) { | |
int leng = strs.length; | |
if (leng == 0) return ""; | |
else if (leng == 1) return strs[0]; | |
// check the minimum length among all strings | |
int minLen = strs[0].length(); | |
String minStr = strs[0]; | |
for (int i = 1; i < leng; i++) { | |
if (strs[i].length() < minLen) { | |
minLen = strs[i].length(); | |
minStr = strs[i]; | |
} | |
} | |
for (int j = 0; j < minLen; j++) { | |
char ch = strs[0].charAt(j); | |
for (int k = 1; k < leng; k++) { | |
char _ch = strs[k].charAt(j); | |
if (ch != _ch) { | |
return minStr.substring(0, j); | |
} | |
} | |
} | |
return minStr; | |
} | |
} |
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class Solution(object): | |
def longestCommonPrefix(self, strs): | |
""" | |
:type strs: List[str] | |
:rtype: str | |
""" | |
strsNum = len(strs) | |
if strsNum == 0: return '' | |
elif strsNum == 1: return strs[0] | |
# check the minimum length among all strings | |
minLen, minStr = len(strs[0]), strs[0] | |
for st in strs: | |
if len(st) < minLen: | |
minLen, minStr = len(st), st | |
# check all string from one index to another | |
for i in range(minLen): | |
c = strs[0][i] | |
for j in range(strsNum): | |
_c = strs[j][i] | |
if c != _c: | |
return minStr[0:i] | |
return minStr |
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