Datetime Benchmark - Given a timestamp in seconds (epoch), return the day of the week

dt_bench.py

from math import ceil
import random

import pytz
from datetime import date
import pandas as pd


def dates_gen(cases: int = 1000) -> list:
    return [random.randint(0, 1639758915) for _ in range(0, cases)]

# dates = [pd.Timestamp]
def get_week_of_month_vj(tss: list):
    # la suma es como un gap, el día 1 del més es el día x de la semana en curso
    dates = [pd.to_datetime(ts, unit='s') for ts in tss]
    return [int(ceil((date.day + date.replace(day=1).day_of_week) / 7.0)) for date in dates]

# dates = [datetime.date]
def get_week_of_month_vf(tss: list) -> list:
    gmt = pytz.timezone("GMT")
    dates = [datetime.datetime.fromtimestamp(ts, gmt) for ts in tss]
    return [int(ceil((date.day + date.replace(day=1).weekday()) / 7.0)) for date in dates]

date_cases = dates_gen(10)

pd_dates = get_week_of_month_vj(tss=date_cases)
dt_dates = get_week_of_month_vf(tss=date_cases)