Created
April 13, 2020 11:37
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Solution for longest increasing subsequence using Dynamic Programming technique (DP)
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sequence = [0, 8, 4, 12, 2, 10, 6, 14, 1, 9, 5, 13, 3, 11, 7, 15] | |
n = len(sequence) | |
lis = [[] for i in range(n)] | |
lis[0].append(sequence[0]) | |
for x in range(1,n): | |
for y in range(x): | |
if sequence[x]> sequence[y] and len(lis[x])< len(lis[y])+1: | |
lis[x]=lis[y].copy() | |
lis[x].append(sequence[x]) | |
k = 1 | |
maxList = lis[0] | |
for p in lis: | |
if len(p) > len(maxList): | |
maxList = p | |
k = len(p) | |
print(f'Longest Increasing Subsequence: {maxList}') | |
print(f'Length: {k}') |
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