fizzbuzz - as short as I can - demo: http://goo.gl/Ssyal

fizzbuzz.js

i=0;do console.log(++i%15?i%3?i%5?i:'buzz':'fizz':'fizzbuzz');while(i<100)

while I'm out to lunch... Hehehe... Can someone try this using node repl... Without the console.log()?

I was out today, but I'm back now. Here's my version, weighing in at 64 characters.

for(i=0;i++<100;)console.log((i%3?'':'Fizz')+(i%5?'':'Buzz')||i)

I think The Cowboy just hit that one out of the park (note that you want 101 and not 100 - because you're missing the last fizzbuzz - still, you win!)

My example counts from 1 to 100!

Doh!

Do I win? No. 63 chars

i=100;while(i--)console.log((i%3?'':'Fizz')+(i%5?'':'Buzz')||i)

@ryanseddon You get an extra FizzBuzz at 0.

FWIW, for(init;condition;) will always be one character less than init;while(condition).. but still, I'd imagine that per the rules, you have to count upwards, from 1 to 100.

62 chars jsconsole output

for(i=0;++i<101;console.log(i%5?f||i:f+'Buzz'))f=i%3?'':'Fizz'