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equivalent of bash command "ls -lt | head -n X" (you have to source it)
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# This bash function is usefull to list most recent things in a directory. | |
# | |
# this script should not be run directly, | |
# instead you need to source it from your .bashrc, | |
# by adding this line: | |
# . ~/bin/lt | |
# | |
lt() { | |
comm="ls" | |
opt="-lt" | |
if [ -n "$LT_SHOW_HIDDEN" ];then | |
if [ $LT_SHOW_HIDDEN -eq 1 ];then | |
opt=$opt"a" | |
fi | |
fi | |
if [ -n "$LT_REVERSE" ];then | |
if [ $LT_REVERSE -eq 1 ];then | |
opt=$opt"r" | |
fi | |
fi | |
num=10 | |
usage="usage: lt [number] [directory_A] [directory_B]\nExample: 'lt 15 /var/log'\nDefault value for number is 10 (see head command)\nIf you do not want to see hidden files, set environment variable 'LT_SHOW_HIDDEN' to 1 before sourcing the lt.sh function.\nYou can also set LT_REVERSE to 1 to get the older files first." | |
re='^[0-9]+$' | |
if [ "$1" = "-h" ] || [ "$1" = "--help" ];then | |
echo $usage | |
elif [ -z "$1" ];then | |
echo "$comm $opt |head -$((num+1))" | |
$comm $opt |head -$((num+1)) | |
elif echo $1 |grep -Eq $re; then | |
num=$1 | |
if [ -z "$2" ];then | |
$comm $opt |head -$((num+1)) | |
else | |
for dir in $@ | |
do | |
shift | |
if [ $dir != $num ]; then | |
echo $dir | |
$comm $opt $dir |head -$((num+1)) | |
fi | |
done | |
fi | |
elif [ -d $1 ]; then | |
# ok, user did not read the usage | |
echo $usage | |
if [ -z "$2" ];then | |
$comm $opt $1 |head -$((num+1)) | |
elif echo $2 |grep -Eq $re;then | |
num=$2 | |
$comm $opt $1 |head -$((num+1)) | |
else | |
echo "The second arg is not a number. I will consider that other args are folders." | |
for dir in $@ | |
do | |
echo $dir | |
$comm $opt $dir |head | |
done | |
fi | |
else | |
if [ -f $1 ]; then | |
$comm $opt $1 | |
else | |
echo $usage; | |
echo "Are you sure that your argument is valid (existing and browsable directory/file) ?" | |
fi; | |
fi; | |
} |
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compatibility with zsh for LT_SHOW_HIDDEN and LT_REVERSE