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December 7, 2017 13:11
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Advent of Code 2017 day 6 solution
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; Returns the index of the largest value | |
(defun maxv (xs) | |
(let* ((idx 1) | |
(mxidx 0) | |
(mxval (aref xs 0))) | |
(while (< idx (length xs)) | |
(if (> (aref xs idx) mxval) | |
(progn | |
(setq mxval (aref xs idx)) | |
(setq mxidx idx))) | |
(setq idx (+ idx 1))) | |
mxidx)) | |
(defun distribute (xs) | |
(let* ((mx-idx (maxv xs)) | |
(mx-val (aref xs mx-idx)) | |
(idx (+ mx-idx 1))) | |
(aset xs mx-idx 0) ;set largest bank to 0 | |
(while (> mx-val 0) | |
(if (>= idx (length xs)) | |
(setq idx 0)) ;check for rollover | |
(aset xs idx (+ (aref xs idx) 1)) | |
(setq mx-val (- mx-val 1)) | |
(setq idx (+ idx 1))) | |
) | |
) | |
(defun solve (raw) | |
(let* ((xs (copy-sequence raw)) | |
(st (make-hash-table :test 'equal)) | |
(cycle nil) | |
(num-steps 0) | |
(num-iters 0)) | |
(while (not cycle) | |
(puthash (md5 (mapconcat 'number-to-string xs ",")) num-steps st) | |
(distribute xs) | |
(setq num-steps (+ num-steps 1)) | |
(if (gethash (md5 (mapconcat 'number-to-string xs ",")) st) | |
(setq cycle t)) | |
) | |
(let ((iter-count (gethash (md5 (mapconcat 'number-to-string xs ",")) st))) | |
`((steps . ,num-steps) | |
(iters-to-cycle . ,(- num-steps iter-count))) | |
) | |
) | |
) |
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