wordle20220119.py

# Wordle - https://www.powerlanguage.co.uk/wordle/

# This little program looks up a suitable word given
# state of the puzzle (from 2022-Jan-19)

# RAISE
# BLIMP
# CHICK
# SWIPE
# UNIFY
# -----

# rems_known = "nip"

def eliminated_letter_in_word(w: str) -> bool:
    eliminated_letters = "raseblmchksweufy"
    for i in eliminated_letters:
        if i in w:
            return True
    return False

count = 0
with open('/usr/share/dict/american-english') as f:
    for w in f:
        if len(w) == 6:
            # NOTE: We look for 6 because w will have newline
            #     (Pdb) print(w.split('.'))
            #     ['Abby\n']
            w = w.rstrip()
            count += 1
            if not eliminated_letter_in_word(w):
                if w[2] == 'i':
                    if 'n' in w and 'p' in w:
                        # The word has 'i' in the middle, and contains
                        # the letters 'n' and 'p'
                        print(w)
print(f"{count} 5-letter words searched")