Created
May 5, 2020 03:39
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Eloquent JavaScript 3.9 递归里面的函数 Python实现
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| def find_solution(target): | |
| def find(current, history): | |
| if current == target: | |
| return history | |
| elif current > target: | |
| return None | |
| else: | |
| return find(current + 5, "({} + 5)".format(history)) or find(current * 3, "({} * 3)".format(history)) | |
| return find(1, "1") |
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