robdmoore

    class Program
    {
        static void Main(string[] args)
        {
            Task.WaitAll(new[] {DoStuff()});
        }

        private static async Task DoStuff()
        {
            var client = new DocumentClient(new Uri("https://<documentdbtenant>.documents.azure.com:443/"),

wbroek

NOTE: Easier way is the X86 way, described on https://www.genymotion.com/help/desktop/faq/#google-play-services

Download the following ZIPs:
    
    ARM Translation Installer v1.1 (http://www.mirrorcreator.com/files/0ZIO8PME/Genymotion-ARM-Translation_v1.1.zip_links)
    
    Download the correct GApps for your Android version:
      Google Apps for Android 6.0 (https://www.androidfilehost.com/?fid=24052804347835438 - benzo-gapps-M-20151011-signed-chroma-r3.zip)
      Google Apps for Android 5.1 (https://www.androidfilehost.com/?fid=96042739161891406 - gapps-L-4-21-15.zip)
      Google Apps for Android 5.0 (https://www.androidfilehost.com/?fid=95784891001614559 - gapps-lp-20141109-signed.zip)

melanke

public class MLRoundedImageView extends ImageView {

	public MLRoundedImageView(Context context) {
		super(context);
	}

	public MLRoundedImageView(Context context, AttributeSet attrs) {
		super(context, attrs);
	}

eligrey

/*
 * object.watch polyfill
 *
 * 2012-04-03
 *
 * By Eli Grey, http://eligrey.com
 * Public Domain.
 * NO WARRANTY EXPRESSED OR IMPLIED. USE AT YOUR OWN RISK.
 */

mathiasbynens

/*!
 * JavaScript function to calculate the destination point given start point latitude / longitude (numeric degrees), bearing (numeric degrees) and distance (in m).
 *
 * Original scripts by Chris Veness
 * Taken from http://movable-type.co.uk/scripts/latlong-vincenty-direct.html and optimized / cleaned up by Mathias Bynens <http://mathiasbynens.be/>
 * Based on the Vincenty direct formula by T. Vincenty, “Direct and Inverse Solutions of Geodesics on the Ellipsoid with application of nested equations”, Survey Review, vol XXII no 176, 1975 <http://www.ngs.noaa.gov/PUBS_LIB/inverse.pdf>
 */
function toRad(n) {
 return n * Math.PI / 180;
};