Created
June 29, 2017 06:01
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Project Euler #31
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def Tree3(s, p, c, L): | |
# attempts the same as &Tree and &Tree2 with a different approach | |
# this assumes that p is ordered from smallest to highest | |
res = 0 | |
lfinal = set() | |
for i in range(len(p)): | |
pos = [L] | |
tSum = c | |
while tSum < s: | |
pos.append(pos[-1]+[p[i]]) | |
tSum += p[i] | |
for j in pos: | |
jSum = sum(j) | |
if jSum > s: continue | |
elif jSum == s: | |
res += 1 | |
lfinal.add(n_from_l(j)) | |
else: | |
n = Tree3(s, p[i+1:], jSum, j) | |
res += n[0] | |
for k in sorted(n[1]): lfinal.add(k) | |
return len(lfinal), lfinal | |
# ans = Tree3(200, [1, 2, 5, 10, 20, 50, 100, 200], 0, []) # at least 5 min of waiting | |
# print(ans[0]) |
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